141113100000 has 288 divisors, whose sum is σ = 473808424320. Its totient is φ = 36751680000.

The previous prime is 141113099987. The next prime is 141113100103. The reversal of 141113100000 is 1311141.

141113100000 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a super-2 number, since 2×141113100000² (a number of 23 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (12).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 12894531 + ... + 12905469.

It is an arithmetic number, because the mean of its divisors is an integer number (1645168140).

Almost surely, 2^141113100000 is an apocalyptic number.

141113100000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 141113100000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (236904212160).

141113100000 is an abundant number, since it is smaller than the sum of its proper divisors (332695324320).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

141113100000 is an equidigital number, since it uses as much as digits as its factorization.

141113100000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11020 (or 10992 counting only the distinct ones).

The product of its (nonzero) digits is 12, while the sum is 12.

Adding to 141113100000 its reverse (1311141), we get a palindrome (141114411141).

The spelling of 141113100000 in words is "one hundred forty-one billion, one hundred thirteen million, one hundred thousand".