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1411133615147 is a prime number
BaseRepresentation
bin10100100010001110000…
…111100010110000101011
311222220101022212001020102
4110202032013202300223
5141110000201141042
63000133230420015
7203644130551304
oct24421607426053
94886338761212
101411133615147
114a4505157123
121a95a196160b
13a30b9414629
144c42913b7ab
1526a907e3b32
hex1488e1e2c2b

1411133615147 has 2 divisors, whose sum is σ = 1411133615148. Its totient is φ = 1411133615146.

The previous prime is 1411133615141. The next prime is 1411133615161. The reversal of 1411133615147 is 7415163311141.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1411133615147 - 26 = 1411133615083 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1411133615147.

It is not a weakly prime, because it can be changed into another prime (1411133615141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 705566807573 + 705566807574.

It is an arithmetic number, because the mean of its divisors is an integer number (705566807574).

Almost surely, 21411133615147 is an apocalyptic number.

1411133615147 is a deficient number, since it is larger than the sum of its proper divisors (1).

1411133615147 is an equidigital number, since it uses as much as digits as its factorization.

1411133615147 is an evil number, because the sum of its binary digits is even.

The product of its digits is 30240, while the sum is 38.

Adding to 1411133615147 its reverse (7415163311141), we get a palindrome (8826296926288).

The spelling of 1411133615147 in words is "one trillion, four hundred eleven billion, one hundred thirty-three million, six hundred fifteen thousand, one hundred forty-seven".