Base | Representation |
---|---|
bin | 10100100010001110000… |
… | …111100010110000101011 |
3 | 11222220101022212001020102 |
4 | 110202032013202300223 |
5 | 141110000201141042 |
6 | 3000133230420015 |
7 | 203644130551304 |
oct | 24421607426053 |
9 | 4886338761212 |
10 | 1411133615147 |
11 | 4a4505157123 |
12 | 1a95a196160b |
13 | a30b9414629 |
14 | 4c42913b7ab |
15 | 26a907e3b32 |
hex | 1488e1e2c2b |
1411133615147 has 2 divisors, whose sum is σ = 1411133615148. Its totient is φ = 1411133615146.
The previous prime is 1411133615141. The next prime is 1411133615161. The reversal of 1411133615147 is 7415163311141.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1411133615147 - 26 = 1411133615083 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1411133615147.
It is not a weakly prime, because it can be changed into another prime (1411133615141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 705566807573 + 705566807574.
It is an arithmetic number, because the mean of its divisors is an integer number (705566807574).
Almost surely, 21411133615147 is an apocalyptic number.
1411133615147 is a deficient number, since it is larger than the sum of its proper divisors (1).
1411133615147 is an equidigital number, since it uses as much as digits as its factorization.
1411133615147 is an evil number, because the sum of its binary digits is even.
The product of its digits is 30240, while the sum is 38.
Adding to 1411133615147 its reverse (7415163311141), we get a palindrome (8826296926288).
The spelling of 1411133615147 in words is "one trillion, four hundred eleven billion, one hundred thirty-three million, six hundred fifteen thousand, one hundred forty-seven".
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