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141113433104222 = 270556716552111
BaseRepresentation
bin100000000101011110001000…
…000011011001111101011110
3200111122022102210001201002112
4200011132020003121331132
5121444000302333313342
61220042341034354022
741503052264360555
oct4005361003317536
9614568383051075
10141113433104222
1140a65964193267
12139b088b28b912
136097c2a51cb47
1426bbcd8860d9c
15114aa3e441682
hex8057880d9f5e

141113433104222 has 4 divisors (see below), whose sum is σ = 211670149656336. Its totient is φ = 70556716552110.

The previous prime is 141113433104209. The next prime is 141113433104263. The reversal of 141113433104222 is 222401334311141.

141113433104222 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×1411134331042222 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 35278358276054 + ... + 35278358276057.

It is an arithmetic number, because the mean of its divisors is an integer number (52917537414084).

Almost surely, 2141113433104222 is an apocalyptic number.

141113433104222 is a deficient number, since it is larger than the sum of its proper divisors (70556716552114).

141113433104222 is an equidigital number, since it uses as much as digits as its factorization.

141113433104222 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 70556716552113.

The product of its (nonzero) digits is 13824, while the sum is 32.

Adding to 141113433104222 its reverse (222401334311141), we get a palindrome (363514767415363).

The spelling of 141113433104222 in words is "one hundred forty-one trillion, one hundred thirteen billion, four hundred thirty-three million, one hundred four thousand, two hundred twenty-two".

Divisors: 1 2 70556716552111 141113433104222