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14111523505433 is a prime number
BaseRepresentation
bin1100110101011001100001…
…0110001000010100011001
31211222001022100002000200202
43031112120112020110121
53322200400004133213
650002424442511545
72654344464454604
oct315263026102431
954861270060622
1014111523505433
11455073314a9a2
1216baaa88055b5
137b4931c82c53
1436b003b1333b
15197116b34b58
hexcd598588519

14111523505433 has 2 divisors, whose sum is σ = 14111523505434. Its totient is φ = 14111523505432.

The previous prime is 14111523505393. The next prime is 14111523505447. The reversal of 14111523505433 is 33450532511141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13570294028944 + 541229476489 = 3683788^2 + 735683^2 .

It is a cyclic number.

It is not a de Polignac number, because 14111523505433 - 224 = 14111506728217 is a prime.

It is not a weakly prime, because it can be changed into another prime (14111523505333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7055761752716 + 7055761752717.

It is an arithmetic number, because the mean of its divisors is an integer number (7055761752717).

Almost surely, 214111523505433 is an apocalyptic number.

It is an amenable number.

14111523505433 is a deficient number, since it is larger than the sum of its proper divisors (1).

14111523505433 is an equidigital number, since it uses as much as digits as its factorization.

14111523505433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 108000, while the sum is 38.

The spelling of 14111523505433 in words is "fourteen trillion, one hundred eleven billion, five hundred twenty-three million, five hundred five thousand, four hundred thirty-three".