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14112017 is a prime number
BaseRepresentation
bin110101110101…
…010100010001
3222112222001022
4311311110101
512103041032
61222245225
7230643623
oct65652421
928488038
1014112017
117a69627
124886815
132c0140a
141c34c13
15138b512
hexd75511

14112017 has 2 divisors, whose sum is σ = 14112018. Its totient is φ = 14112016.

The previous prime is 14112011. The next prime is 14112019. The reversal of 14112017 is 71021141.

14112017 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12327121 + 1784896 = 3511^2 + 1336^2 .

It is a cyclic number.

It is not a de Polignac number, because 14112017 - 26 = 14111953 is a prime.

Together with 14112019, it forms a pair of twin primes.

It is a Chen prime.

It is a nialpdrome in base 16.

It is a junction number, because it is equal to n+sod(n) for n = 14111986 and 14112004.

It is not a weakly prime, because it can be changed into another prime (14112011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7056008 + 7056009.

It is an arithmetic number, because the mean of its divisors is an integer number (7056009).

Almost surely, 214112017 is an apocalyptic number.

It is an amenable number.

14112017 is a deficient number, since it is larger than the sum of its proper divisors (1).

14112017 is an equidigital number, since it uses as much as digits as its factorization.

14112017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 56, while the sum is 17.

The square root of 14112017 is about 3756.5964648868. The cubic root of 14112017 is about 241.6553217557.

Adding to 14112017 its reverse (71021141), we get a palindrome (85133158).

The spelling of 14112017 in words is "fourteen million, one hundred twelve thousand, seventeen".