Search a number
-
+
14112034403557 is a prime number
BaseRepresentation
bin1100110101011011011011…
…0011000011010011100101
31211222002121221102100011111
43031112312303003103211
53322202421301403212
650002551253105021
72654363240151526
oct315266663032345
954862557370144
1014112034403557
114550975580252
1216bb00b928171
137b49b3a8262c
1436b05190484d
15197146901ea7
hexcd5b6cc34e5

14112034403557 has 2 divisors, whose sum is σ = 14112034403558. Its totient is φ = 14112034403556.

The previous prime is 14112034403521. The next prime is 14112034403569. The reversal of 14112034403557 is 75530443021141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13392445265761 + 719589137796 = 3659569^2 + 848286^2 .

It is a cyclic number.

It is not a de Polignac number, because 14112034403557 - 239 = 13562278589669 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14112034413557) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7056017201778 + 7056017201779.

It is an arithmetic number, because the mean of its divisors is an integer number (7056017201779).

Almost surely, 214112034403557 is an apocalyptic number.

It is an amenable number.

14112034403557 is a deficient number, since it is larger than the sum of its proper divisors (1).

14112034403557 is an equidigital number, since it uses as much as digits as its factorization.

14112034403557 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 201600, while the sum is 40.

Adding to 14112034403557 its reverse (75530443021141), we get a palindrome (89642477424698).

The spelling of 14112034403557 in words is "fourteen trillion, one hundred twelve billion, thirty-four million, four hundred three thousand, five hundred fifty-seven".