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141121114314001 is a prime number
BaseRepresentation
bin100000000101100101010001…
…111000111001010100010001
3200111200001021002121121000121
4200011211101320321110101
5121444112020231022001
61220050051145350241
741503443524521303
oct4005452170712421
9614601232547017
10141121114314001
1140a69146012918
12139b2273798381
1360988829b65a3
1426bc426a63973
15114ad3d96a6a1
hex805951e39511

141121114314001 has 2 divisors, whose sum is σ = 141121114314002. Its totient is φ = 141121114314000.

The previous prime is 141121114313929. The next prime is 141121114314077. The reversal of 141121114314001 is 100413411121141.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 132689780001025 + 8431334312976 = 11519105^2 + 2903676^2 .

It is a cyclic number.

It is not a de Polignac number, because 141121114314001 - 217 = 141121114182929 is a prime.

It is not a weakly prime, because it can be changed into another prime (141121114314101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70560557157000 + 70560557157001.

It is an arithmetic number, because the mean of its divisors is an integer number (70560557157001).

Almost surely, 2141121114314001 is an apocalyptic number.

It is an amenable number.

141121114314001 is a deficient number, since it is larger than the sum of its proper divisors (1).

141121114314001 is an equidigital number, since it uses as much as digits as its factorization.

141121114314001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 384, while the sum is 25.

Adding to 141121114314001 its reverse (100413411121141), we get a palindrome (241534525435142).

The spelling of 141121114314001 in words is "one hundred forty-one trillion, one hundred twenty-one billion, one hundred fourteen million, three hundred fourteen thousand, one".