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141122301101 is a prime number
BaseRepresentation
bin1000001101101110001…
…0110110110010101101
3111111021001111200102122
42003123202312302231
54303004302113401
6144455232402325
713124066524115
oct2033342666255
9444231450378
10141122301101
1154938950611
12234256a63a5
13104002505a2
146b8a6d4045
153a0e51021b
hex20db8b6cad

141122301101 has 2 divisors, whose sum is σ = 141122301102. Its totient is φ = 141122301100.

The previous prime is 141122301091. The next prime is 141122301157. The reversal of 141122301101 is 101103221141.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 131660848201 + 9461452900 = 362851^2 + 97270^2 .

It is a cyclic number.

It is not a de Polignac number, because 141122301101 - 222 = 141118106797 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 141122301101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (141122301181) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70561150550 + 70561150551.

It is an arithmetic number, because the mean of its divisors is an integer number (70561150551).

Almost surely, 2141122301101 is an apocalyptic number.

It is an amenable number.

141122301101 is a deficient number, since it is larger than the sum of its proper divisors (1).

141122301101 is an equidigital number, since it uses as much as digits as its factorization.

141122301101 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 141122301101 its reverse (101103221141), we get a palindrome (242225522242).

The spelling of 141122301101 in words is "one hundred forty-one billion, one hundred twenty-two million, three hundred one thousand, one hundred one".