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1411223112193 is a prime number
BaseRepresentation
bin10100100010010011011…
…100111100101000000001
311222220121120020222002211
4110202103130330220001
5141110141104042233
63000150144542121
7203646265350526
oct24422334745001
94886546228084
101411223112193
114a4550724624
121a9607921941
13a3101b1b66b
144c436d9714d
1526a985c15cd
hex1489373ca01

1411223112193 has 2 divisors, whose sum is σ = 1411223112194. Its totient is φ = 1411223112192.

The previous prime is 1411223112181. The next prime is 1411223112223. The reversal of 1411223112193 is 3912113221141.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1317153314929 + 94069797264 = 1147673^2 + 306708^2 .

It is an emirp because it is prime and its reverse (3912113221141) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1411223112193 - 221 = 1411221015041 is a prime.

It is not a weakly prime, because it can be changed into another prime (1411223112133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 705611556096 + 705611556097.

It is an arithmetic number, because the mean of its divisors is an integer number (705611556097).

Almost surely, 21411223112193 is an apocalyptic number.

It is an amenable number.

1411223112193 is a deficient number, since it is larger than the sum of its proper divisors (1).

1411223112193 is an equidigital number, since it uses as much as digits as its factorization.

1411223112193 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2592, while the sum is 31.

The spelling of 1411223112193 in words is "one trillion, four hundred eleven billion, two hundred twenty-three million, one hundred twelve thousand, one hundred ninety-three".