Base | Representation |
---|---|
bin | 10100100010010011100… |
… | …000111000010000011001 |
3 | 11222220121122012022221011 |
4 | 110202103200320100121 |
5 | 141110141340032443 |
6 | 3000150223013521 |
7 | 203646310202446 |
oct | 24422340702031 |
9 | 4886548168834 |
10 | 1411224142873 |
11 | 4a4551268a26 |
12 | 1a960813a2a1 |
13 | a31020bc82c |
14 | 4c4371849cd |
15 | 26a98726b9d |
hex | 14893838419 |
1411224142873 has 2 divisors, whose sum is σ = 1411224142874. Its totient is φ = 1411224142872.
The previous prime is 1411224142831. The next prime is 1411224142879. The reversal of 1411224142873 is 3782414221141.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1057754654784 + 353469488089 = 1028472^2 + 594533^2 .
It is an emirp because it is prime and its reverse (3782414221141) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1411224142873 - 217 = 1411224011801 is a prime.
It is not a weakly prime, because it can be changed into another prime (1411224142879) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 705612071436 + 705612071437.
It is an arithmetic number, because the mean of its divisors is an integer number (705612071437).
Almost surely, 21411224142873 is an apocalyptic number.
It is an amenable number.
1411224142873 is a deficient number, since it is larger than the sum of its proper divisors (1).
1411224142873 is an equidigital number, since it uses as much as digits as its factorization.
1411224142873 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 86016, while the sum is 40.
The spelling of 1411224142873 in words is "one trillion, four hundred eleven billion, two hundred twenty-four million, one hundred forty-two thousand, eight hundred seventy-three".
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