Base | Representation |
---|---|
bin | 10100100010010011100… |
… | …000111000001111101111 |
3 | 11222220121122012022212121 |
4 | 110202103200320033233 |
5 | 141110141340032311 |
6 | 3000150223013411 |
7 | 203646310202356 |
oct | 24422340701757 |
9 | 4886548168777 |
10 | 1411224142831 |
11 | 4a4551268998 |
12 | 1a960813a267 |
13 | a31020bc7c9 |
14 | 4c43718499d |
15 | 26a98726b71 |
hex | 148938383ef |
1411224142831 has 2 divisors, whose sum is σ = 1411224142832. Its totient is φ = 1411224142830.
The previous prime is 1411224142799. The next prime is 1411224142873. The reversal of 1411224142831 is 1382414221141.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1411224142831 - 25 = 1411224142799 is a prime.
It is a super-2 number, since 2×14112241428312 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1411224140831) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 705612071415 + 705612071416.
It is an arithmetic number, because the mean of its divisors is an integer number (705612071416).
Almost surely, 21411224142831 is an apocalyptic number.
1411224142831 is a deficient number, since it is larger than the sum of its proper divisors (1).
1411224142831 is an equidigital number, since it uses as much as digits as its factorization.
1411224142831 is an evil number, because the sum of its binary digits is even.
The product of its digits is 12288, while the sum is 34.
Adding to 1411224142831 its reverse (1382414221141), we get a palindrome (2793638363972).
The spelling of 1411224142831 in words is "one trillion, four hundred eleven billion, two hundred twenty-four million, one hundred forty-two thousand, eight hundred thirty-one".
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