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141122431210231 is a prime number
BaseRepresentation
bin100000000101100110100000…
…011000011101001011110111
3200111200011122212120212001001
4200011212200120131023313
5121444122214342211411
61220050425551144131
741503521255123022
oct4005464030351367
9614604585525031
10141122431210231
1140a69761400509
12139b2580815047
136098a32789023
1426bc50d9021b9
15114adb9396dc1
hex8059a061d2f7

141122431210231 has 2 divisors, whose sum is σ = 141122431210232. Its totient is φ = 141122431210230.

The previous prime is 141122431210193. The next prime is 141122431210283. The reversal of 141122431210231 is 132012134221141.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 141122431210231 - 227 = 141122296992503 is a prime.

It is a super-2 number, since 2×1411224312102312 (a number of 29 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 141122431210231.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (141122431214231) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70561215605115 + 70561215605116.

It is an arithmetic number, because the mean of its divisors is an integer number (70561215605116).

Almost surely, 2141122431210231 is an apocalyptic number.

141122431210231 is a deficient number, since it is larger than the sum of its proper divisors (1).

141122431210231 is an equidigital number, since it uses as much as digits as its factorization.

141122431210231 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2304, while the sum is 28.

Adding to 141122431210231 its reverse (132012134221141), we get a palindrome (273134565431372).

The spelling of 141122431210231 in words is "one hundred forty-one trillion, one hundred twenty-two billion, four hundred thirty-one million, two hundred ten thousand, two hundred thirty-one".