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141122441323 is a prime number
BaseRepresentation
bin1000001101101110001…
…1011001000001101011
3111111021001202210210001
42003123203121001223
54303004321110243
6144455235403431
713124100646663
oct2033343310153
9444231683701
10141122441323
1154938a369a6
1223425753577
131040029c366
146b8a72d1a3
153a0e53ba4d
hex20db8d906b

141122441323 has 2 divisors, whose sum is σ = 141122441324. Its totient is φ = 141122441322.

The previous prime is 141122441297. The next prime is 141122441357. The reversal of 141122441323 is 323144221141.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 141122441323 - 237 = 3683487851 is a prime.

It is a super-3 number, since 3×1411224413233 (a number of 34 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 141122441291 and 141122441300.

It is not a weakly prime, because it can be changed into another prime (141122441393) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70561220661 + 70561220662.

It is an arithmetic number, because the mean of its divisors is an integer number (70561220662).

Almost surely, 2141122441323 is an apocalyptic number.

141122441323 is a deficient number, since it is larger than the sum of its proper divisors (1).

141122441323 is an equidigital number, since it uses as much as digits as its factorization.

141122441323 is an evil number, because the sum of its binary digits is even.

The product of its digits is 4608, while the sum is 28.

Adding to 141122441323 its reverse (323144221141), we get a palindrome (464266662464).

The spelling of 141122441323 in words is "one hundred forty-one billion, one hundred twenty-two million, four hundred forty-one thousand, three hundred twenty-three".