141123130055040 has 512 divisors, whose sum is σ = 524508668006400. Its totient is φ = 31606647054336.

The previous prime is 141123130055027. The next prime is 141123130055051. The reversal of 141123130055040 is 40550031321141.

It is a Harshad number since it is a multiple of its sum of digits (30).

It is a junction number, because it is equal to n+sod(n) for n = 141123130054989 and 141123130055007.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 243148867 + ... + 243728573.

It is an arithmetic number, because the mean of its divisors is an integer number (1024430992200).

Almost surely, 2^{141123130055040} is an apocalyptic number.

141123130055040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 141123130055040, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (262254334003200).

141123130055040 is an abundant number, since it is smaller than the sum of its proper divisors (383385537951360).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

141123130055040 is a wasteful number, since it uses less digits than its factorization.

141123130055040 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 580102 (or 580090 counting only the distinct ones).

The product of its (nonzero) digits is 7200, while the sum is 30.

Adding to 141123130055040 its reverse (40550031321141), we get a palindrome (181673161376181).

The spelling of 141123130055040 in words is "one hundred forty-one trillion, one hundred twenty-three billion, one hundred thirty million, fifty-five thousand, forty".