141123303321141 has 4 divisors (see below), whose sum is σ = 188164404428192. Its totient is φ = 94082202214092.

The previous prime is 141123303321113. The next prime is 141123303321229.

It is a happy number.

141123303321141 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 141123303321141 - 2³⁵ = 141088943582773 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 141123303321099 and 141123303321108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (141123303321101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23520550553521 + ... + 23520550553526.

It is an arithmetic number, because the mean of its divisors is an integer number (47041101107048).

Almost surely, 2^{141123303321141} is an apocalyptic number.

It is an amenable number.

141123303321141 is a deficient number, since it is larger than the sum of its proper divisors (47041101107051).

141123303321141 is an equidigital number, since it uses as much as digits as its factorization.

141123303321141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 47041101107050.

The product of its (nonzero) digits is 5184, while the sum is 30.

It can be divided in two parts, 14112330 and 3321141, that added together give a palindrome (17433471).

The spelling of 141123303321141 in words is "one hundred forty-one trillion, one hundred twenty-three billion, three hundred three million, three hundred twenty-one thousand, one hundred forty-one".