Base | Representation |
---|---|
bin | 1000001101101110011… |
… | …0110100011101110111 |
3 | 111111021010110110201222 |
4 | 2003123212310131313 |
5 | 4303010033341101 |
6 | 144455310540555 |
7 | 13124111412323 |
oct | 2033346643567 |
9 | 444233413658 |
10 | 141123340151 |
11 | 549394a0232 |
12 | 23425b0775b |
13 | 10400525501 |
14 | 6b8a8c4983 |
15 | 3a0e66801b |
hex | 20db9b4777 |
141123340151 has 2 divisors, whose sum is σ = 141123340152. Its totient is φ = 141123340150.
The previous prime is 141123340091. The next prime is 141123340159. The reversal of 141123340151 is 151043321141.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 141123340151 - 210 = 141123339127 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 141123340151.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (141123340159) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70561670075 + 70561670076.
It is an arithmetic number, because the mean of its divisors is an integer number (70561670076).
Almost surely, 2141123340151 is an apocalyptic number.
141123340151 is a deficient number, since it is larger than the sum of its proper divisors (1).
141123340151 is an equidigital number, since it uses as much as digits as its factorization.
141123340151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1440, while the sum is 26.
Adding to 141123340151 its reverse (151043321141), we get a palindrome (292166661292).
The spelling of 141123340151 in words is "one hundred forty-one billion, one hundred twenty-three million, three hundred forty thousand, one hundred fifty-one".
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