141123423002130 has 48 divisors (see below), whose sum is σ = 367173426573720. Its totient is φ = 37607012619264.

The previous prime is 141123423002113. The next prime is 141123423002147. The reversal of 141123423002130 is 31200324321141.

141123423002130 is a `hidden beast` number, since 1 + 4 + 1 + 1 + 2 + 342 + 300 + 2 + 13 + 0 = 666.

It is an interprime number because it is at equal distance from previous prime (141123423002113) and next prime (141123423002147).

It can be written as a sum of positive squares in 4 ways, for example, as 139589097337089 + 1534325665041 = 11814783^2 + 1238679^2 .

It is a super-2 number, since 2×141123423002130² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 141123423002094 and 141123423002103.

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 539455615 + ... + 539717154.

Almost surely, 2^{141123423002130} is an apocalyptic number.

141123423002130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

141123423002130 is an abundant number, since it is smaller than the sum of its proper divisors (226050003571590).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

141123423002130 is a wasteful number, since it uses less digits than its factorization.

141123423002130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1079174235 (or 1079174232 counting only the distinct ones).

The product of its (nonzero) digits is 3456, while the sum is 27.

Adding to 141123423002130 its reverse (31200324321141), we get a palindrome (172323747323271).

The spelling of 141123423002130 in words is "one hundred forty-one trillion, one hundred twenty-three billion, four hundred twenty-three million, two thousand, one hundred thirty".