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141123425424211 is a prime number
BaseRepresentation
bin100000000101100111011011…
…101001000101001101010011
3200111200021020011101011020001
4200011213123221011031103
5121444131233402033321
61220051112344430431
741503555016605036
oct4005473351051523
9614607204334201
10141123425424211
1140a6a12163215a
12139b27b9778417
136098b6074b719
1426bc5a598501d
15114ae267d3c91
hex8059dba45353

141123425424211 has 2 divisors, whose sum is σ = 141123425424212. Its totient is φ = 141123425424210.

The previous prime is 141123425424209. The next prime is 141123425424253. The reversal of 141123425424211 is 112424524321141.

It is a weak prime.

It is an emirp because it is prime and its reverse (112424524321141) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 141123425424211 - 21 = 141123425424209 is a prime.

Together with 141123425424209, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (141123425424271) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70561712712105 + 70561712712106.

It is an arithmetic number, because the mean of its divisors is an integer number (70561712712106).

Almost surely, 2141123425424211 is an apocalyptic number.

141123425424211 is a deficient number, since it is larger than the sum of its proper divisors (1).

141123425424211 is an equidigital number, since it uses as much as digits as its factorization.

141123425424211 is an evil number, because the sum of its binary digits is even.

The product of its digits is 61440, while the sum is 37.

Adding to 141123425424211 its reverse (112424524321141), we get a palindrome (253547949745352).

The spelling of 141123425424211 in words is "one hundred forty-one trillion, one hundred twenty-three billion, four hundred twenty-five million, four hundred twenty-four thousand, two hundred eleven".