14112434311300 has 36 divisors (see below), whose sum is σ = 32979673416676. Its totient is φ = 5210744976000.

The previous prime is 14112434311273. The next prime is 14112434311301. The reversal of 14112434311300 is 311343421141.

It can be written as a sum of positive squares in 6 ways, for example, as 5020906784644 + 9091527526656 = 2240738^2 + 3015216^2 .

It is not an unprimeable number, because it can be changed into a prime (14112434311301) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 5427858051 + ... + 5427860650.

Almost surely, 2^{14112434311300} is an apocalyptic number.

14112434311300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

14112434311300 is an abundant number, since it is smaller than the sum of its proper divisors (18867239105376).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

14112434311300 is a wasteful number, since it uses less digits than its factorization.

14112434311300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10855718728 (or 10855718721 counting only the distinct ones).

The product of its (nonzero) digits is 3456, while the sum is 28.

Adding to 14112434311300 its reverse (311343421141), we get a palindrome (14423777732441).

The spelling of 14112434311300 in words is "fourteen trillion, one hundred twelve billion, four hundred thirty-four million, three hundred eleven thousand, three hundred".