Base | Representation |
---|---|
bin | 100000000101101000111111… |
… | …100010111000100010010011 |
3 | 200111200102112222020200211111 |
4 | 200011220333202320202103 |
5 | 121444143201442133133 |
6 | 1220051550541154151 |
7 | 41503644401313523 |
oct | 4005507742704223 |
9 | 614612488220744 |
10 | 141125101521043 |
11 | 40a6a901759552 |
12 | 139b2ba6b5b957 |
13 | 6099069a790b3 |
14 | 26bc6c4407683 |
15 | 114aec3a151cd |
hex | 805a3f8b8893 |
141125101521043 has 2 divisors, whose sum is σ = 141125101521044. Its totient is φ = 141125101521042.
The previous prime is 141125101521017. The next prime is 141125101521143. The reversal of 141125101521043 is 340125101521141.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 141125101521043 - 225 = 141125067966611 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 141125101520996 and 141125101521014.
It is not a weakly prime, because it can be changed into another prime (141125101521143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70562550760521 + 70562550760522.
It is an arithmetic number, because the mean of its divisors is an integer number (70562550760522).
Almost surely, 2141125101521043 is an apocalyptic number.
141125101521043 is a deficient number, since it is larger than the sum of its proper divisors (1).
141125101521043 is an equidigital number, since it uses as much as digits as its factorization.
141125101521043 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4800, while the sum is 31.
The spelling of 141125101521043 in words is "one hundred forty-one trillion, one hundred twenty-five billion, one hundred one million, five hundred twenty-one thousand, forty-three".
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