Base | Representation |
---|---|
bin | 100000000101101000111111… |
… | …100010111000100011110111 |
3 | 200111200102112222020200222012 |
4 | 200011220333202320203313 |
5 | 121444143201442134033 |
6 | 1220051550541154435 |
7 | 41503644401314025 |
oct | 4005507742704367 |
9 | 614612488220865 |
10 | 141125101521143 |
11 | 40a6a901759633 |
12 | 139b2ba6b5ba1b |
13 | 6099069a7915c |
14 | 26bc6c4407715 |
15 | 114aec3a15248 |
hex | 805a3f8b88f7 |
141125101521143 has 2 divisors, whose sum is σ = 141125101521144. Its totient is φ = 141125101521142.
The previous prime is 141125101521043. The next prime is 141125101521167. The reversal of 141125101521143 is 341125101521141.
141125101521143 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 141125101521143 - 216 = 141125101455607 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (141125101521043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70562550760571 + 70562550760572.
It is an arithmetic number, because the mean of its divisors is an integer number (70562550760572).
Almost surely, 2141125101521143 is an apocalyptic number.
141125101521143 is a deficient number, since it is larger than the sum of its proper divisors (1).
141125101521143 is an equidigital number, since it uses as much as digits as its factorization.
141125101521143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4800, while the sum is 32.
The spelling of 141125101521143 in words is "one hundred forty-one trillion, one hundred twenty-five billion, one hundred one million, five hundred twenty-one thousand, one hundred forty-three".
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