Base | Representation |
---|---|
bin | 11010010010010101… |
… | …11110001110010111 |
3 | 1100102112012001002112 |
4 | 31021022332032113 |
5 | 212400300434332 |
6 | 10252212101235 |
7 | 1006502253335 |
oct | 151112761627 |
9 | 40375161075 |
10 | 14112514967 |
11 | 5a92168411 |
12 | 289a30481b |
13 | 143ba14b95 |
14 | 97c404b55 |
15 | 578e5adb2 |
hex | 3492be397 |
14112514967 has 2 divisors, whose sum is σ = 14112514968. Its totient is φ = 14112514966.
The previous prime is 14112514939. The next prime is 14112515029. The reversal of 14112514967 is 76941521141.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14112514967 - 214 = 14112498583 is a prime.
It is a super-2 number, since 2×141125149672 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14112514937) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7056257483 + 7056257484.
It is an arithmetic number, because the mean of its divisors is an integer number (7056257484).
Almost surely, 214112514967 is an apocalyptic number.
14112514967 is a deficient number, since it is larger than the sum of its proper divisors (1).
14112514967 is an equidigital number, since it uses as much as digits as its factorization.
14112514967 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 60480, while the sum is 41.
The spelling of 14112514967 in words is "fourteen billion, one hundred twelve million, five hundred fourteen thousand, nine hundred sixty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •