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14112514967 is a prime number
BaseRepresentation
bin11010010010010101…
…11110001110010111
31100102112012001002112
431021022332032113
5212400300434332
610252212101235
71006502253335
oct151112761627
940375161075
1014112514967
115a92168411
12289a30481b
13143ba14b95
1497c404b55
15578e5adb2
hex3492be397

14112514967 has 2 divisors, whose sum is σ = 14112514968. Its totient is φ = 14112514966.

The previous prime is 14112514939. The next prime is 14112515029. The reversal of 14112514967 is 76941521141.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 14112514967 - 214 = 14112498583 is a prime.

It is a super-2 number, since 2×141125149672 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14112514937) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7056257483 + 7056257484.

It is an arithmetic number, because the mean of its divisors is an integer number (7056257484).

Almost surely, 214112514967 is an apocalyptic number.

14112514967 is a deficient number, since it is larger than the sum of its proper divisors (1).

14112514967 is an equidigital number, since it uses as much as digits as its factorization.

14112514967 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 60480, while the sum is 41.

The spelling of 14112514967 in words is "fourteen billion, one hundred twelve million, five hundred fourteen thousand, nine hundred sixty-seven".