Base | Representation |
---|---|
bin | 1100110101011101001111… |
… | …0000011010001111000100 |
3 | 1211222010212210121220121121 |
4 | 3031113103300122033010 |
5 | 3322204420141002213 |
6 | 50003111410323324 |
7 | 2654411256610414 |
oct | 315272360321704 |
9 | 54863783556547 |
10 | 14112520250308 |
11 | 45510a4850097 |
12 | 16bb126589544 |
13 | 7b4a6062060c |
14 | 36b09a254644 |
15 | 1971743c188d |
hex | cd5d3c1a3c4 |
14112520250308 has 24 divisors (see below), whose sum is σ = 25277231376320. Its totient is φ = 6890531729760.
The previous prime is 14112520250299. The next prime is 14112520250317. The reversal of 14112520250308 is 80305202521141.
14112520250308 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is an interprime number because it is at equal distance from previous prime (14112520250299) and next prime (14112520250317).
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 8968503 + ... + 10423966.
Almost surely, 214112520250308 is an apocalyptic number.
It is an amenable number.
14112520250308 is a deficient number, since it is larger than the sum of its proper divisors (11164711126012).
14112520250308 is a wasteful number, since it uses less digits than its factorization.
14112520250308 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 19396747 (or 19396745 counting only the distinct ones).
The product of its (nonzero) digits is 19200, while the sum is 34.
Adding to 14112520250308 its reverse (80305202521141), we get a palindrome (94417722771449).
The spelling of 14112520250308 in words is "fourteen trillion, one hundred twelve billion, five hundred twenty million, two hundred fifty thousand, three hundred eight".
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