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14112520250341 = 1491279550313457
BaseRepresentation
bin1100110101011101001111…
…0000011010001111100101
31211222010212210121220122211
43031113103300122033211
53322204420141002331
650003111410323421
72654411256610462
oct315272360321745
954863783556584
1014112520250341
1145510a4850117
1216bb126589571
137b4a60620636
1436b09a254669
151971743c18b1
hexcd5d3c1a3e5

14112520250341 has 16 divisors (see below), whose sum is σ = 14221983744000. Its totient is φ = 14003259395328.

The previous prime is 14112520250321. The next prime is 14112520250363. The reversal of 14112520250341 is 14305202521141.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14112520250341 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14112520250321) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1048705485 + ... + 1048718941.

It is an arithmetic number, because the mean of its divisors is an integer number (888873984000).

Almost surely, 214112520250341 is an apocalyptic number.

It is an amenable number.

14112520250341 is a deficient number, since it is larger than the sum of its proper divisors (109463493659).

14112520250341 is a wasteful number, since it uses less digits than its factorization.

14112520250341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 20388.

The product of its (nonzero) digits is 9600, while the sum is 31.

Adding to 14112520250341 its reverse (14305202521141), we get a palindrome (28417722771482).

The spelling of 14112520250341 in words is "fourteen trillion, one hundred twelve billion, five hundred twenty million, two hundred fifty thousand, three hundred forty-one".

Divisors: 1 149 1279 5503 13457 190571 819947 2005093 7038337 17211503 74053871 1048712213 2564513947 11034026779 94714901009 14112520250341