Base | Representation |
---|---|
bin | 1100110101011101001111… |
… | …0000011010001111100110 |
3 | 1211222010212210121220122212 |
4 | 3031113103300122033212 |
5 | 3322204420141002332 |
6 | 50003111410323422 |
7 | 2654411256610463 |
oct | 315272360321746 |
9 | 54863783556585 |
10 | 14112520250342 |
11 | 45510a4850118 |
12 | 16bb126589572 |
13 | 7b4a60620637 |
14 | 36b09a25466a |
15 | 1971743c18b2 |
hex | cd5d3c1a3e6 |
14112520250342 has 16 divisors (see below), whose sum is σ = 21247443925200. Its totient is φ = 7030063858848.
The previous prime is 14112520250321. The next prime is 14112520250363. The reversal of 14112520250342 is 24305202521141.
It is an interprime number because it is at equal distance from previous prime (14112520250321) and next prime (14112520250363).
It is a super-2 number, since 2×141125202503422 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 14112520250299 and 14112520250308.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5095217 + ... + 7361132.
It is an arithmetic number, because the mean of its divisors is an integer number (1327965245325).
Almost surely, 214112520250342 is an apocalyptic number.
14112520250342 is a deficient number, since it is larger than the sum of its proper divisors (7134923674858).
14112520250342 is a wasteful number, since it uses less digits than its factorization.
14112520250342 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12458455.
The product of its (nonzero) digits is 19200, while the sum is 32.
Adding to 14112520250342 its reverse (24305202521141), we get a palindrome (38417722771483).
The spelling of 14112520250342 in words is "fourteen trillion, one hundred twelve billion, five hundred twenty million, two hundred fifty thousand, three hundred forty-two".
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