Base | Representation |
---|---|
bin | 1100110101011101001111… |
… | …0000011010001111100111 |
3 | 1211222010212210121220122220 |
4 | 3031113103300122033213 |
5 | 3322204420141002333 |
6 | 50003111410323423 |
7 | 2654411256610464 |
oct | 315272360321747 |
9 | 54863783556586 |
10 | 14112520250343 |
11 | 45510a4850119 |
12 | 16bb126589573 |
13 | 7b4a60620638 |
14 | 36b09a25466b |
15 | 1971743c18b3 |
hex | cd5d3c1a3e7 |
14112520250343 has 8 divisors (see below), whose sum is σ = 18838052006256. Its totient is φ = 9397667664000.
The previous prime is 14112520250321. The next prime is 14112520250363. The reversal of 14112520250343 is 34305202521141.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 14112520250343 - 213 = 14112520242151 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14112520250363) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2669789308 + ... + 2669794593.
It is an arithmetic number, because the mean of its divisors is an integer number (2354756500782).
Almost surely, 214112520250343 is an apocalyptic number.
14112520250343 is a deficient number, since it is larger than the sum of its proper divisors (4725531755913).
14112520250343 is an equidigital number, since it uses as much as digits as its factorization.
14112520250343 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5339584785.
The product of its (nonzero) digits is 28800, while the sum is 33.
Adding to 14112520250343 its reverse (34305202521141), we get a palindrome (48417722771484).
The spelling of 14112520250343 in words is "fourteen trillion, one hundred twelve billion, five hundred twenty million, two hundred fifty thousand, three hundred forty-three".
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