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14112520250343 = 38815339583901
BaseRepresentation
bin1100110101011101001111…
…0000011010001111100111
31211222010212210121220122220
43031113103300122033213
53322204420141002333
650003111410323423
72654411256610464
oct315272360321747
954863783556586
1014112520250343
1145510a4850119
1216bb126589573
137b4a60620638
1436b09a25466b
151971743c18b3
hexcd5d3c1a3e7

14112520250343 has 8 divisors (see below), whose sum is σ = 18838052006256. Its totient is φ = 9397667664000.

The previous prime is 14112520250321. The next prime is 14112520250363. The reversal of 14112520250343 is 34305202521141.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 14112520250343 - 213 = 14112520242151 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14112520250363) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2669789308 + ... + 2669794593.

It is an arithmetic number, because the mean of its divisors is an integer number (2354756500782).

Almost surely, 214112520250343 is an apocalyptic number.

14112520250343 is a deficient number, since it is larger than the sum of its proper divisors (4725531755913).

14112520250343 is an equidigital number, since it uses as much as digits as its factorization.

14112520250343 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5339584785.

The product of its (nonzero) digits is 28800, while the sum is 33.

Adding to 14112520250343 its reverse (34305202521141), we get a palindrome (48417722771484).

The spelling of 14112520250343 in words is "fourteen trillion, one hundred twelve billion, five hundred twenty million, two hundred fifty thousand, three hundred forty-three".

Divisors: 1 3 881 2643 5339583901 16018751703 4704173416781 14112520250343