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141130420222201 is a prime number
BaseRepresentation
bin100000000101101101111100…
…100100000111100011111001
3200111200221021122022201012021
4200011231330210013203321
5121444240100034102301
61220054230415314441
741504223243450064
oct4005557444074371
9614627248281167
10141130420222201
1140a72090a53443
12139b403021ba21
136099706952947
1426bca6a9498db
15114b1d59218a1
hex805b7c9078f9

141130420222201 has 2 divisors, whose sum is σ = 141130420222202. Its totient is φ = 141130420222200.

The previous prime is 141130420222157. The next prime is 141130420222243. The reversal of 141130420222201 is 102222024031141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 75822994369600 + 65307425852601 = 8707640^2 + 8081301^2 .

It is a cyclic number.

It is not a de Polignac number, because 141130420222201 - 233 = 141121830287609 is a prime.

It is not a weakly prime, because it can be changed into another prime (141130420222261) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70565210111100 + 70565210111101.

It is an arithmetic number, because the mean of its divisors is an integer number (70565210111101).

Almost surely, 2141130420222201 is an apocalyptic number.

It is an amenable number.

141130420222201 is a deficient number, since it is larger than the sum of its proper divisors (1).

141130420222201 is an equidigital number, since it uses as much as digits as its factorization.

141130420222201 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 141130420222201 its reverse (102222024031141), we get a palindrome (243352444253342).

The spelling of 141130420222201 in words is "one hundred forty-one trillion, one hundred thirty billion, four hundred twenty million, two hundred twenty-two thousand, two hundred one".