Base | Representation |
---|---|
bin | 100000000101101110100111… |
… | …101110010101100100100000 |
3 | 200111201000011002211202102212 |
4 | 200011232213232111210200 |
5 | 121444243040421240222 |
6 | 1220054430323301252 |
7 | 41504250215262155 |
oct | 4005564756254440 |
9 | 614630132752385 |
10 | 141131144321312 |
11 | 40a72422762862 |
12 | 139b41b281a828 |
13 | 60997c097c162 |
14 | 26bcad8b9822c |
15 | 114b2292a46e2 |
hex | 805ba7b95920 |
141131144321312 has 48 divisors (see below), whose sum is σ = 289004333232384. Its totient is φ = 67767971232000.
The previous prime is 141131144321309. The next prime is 141131144321371. The reversal of 141131144321312 is 213123441131141.
It is a Harshad number since it is a multiple of its sum of digits (32).
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 542882639 + ... + 543142542.
It is an arithmetic number, because the mean of its divisors is an integer number (6020923609008).
Almost surely, 2141131144321312 is an apocalyptic number.
It is an amenable number.
141131144321312 is an abundant number, since it is smaller than the sum of its proper divisors (147873188911072).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
141131144321312 is a wasteful number, since it uses less digits than its factorization.
141131144321312 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1086025353 (or 1086025345 counting only the distinct ones).
The product of its digits is 6912, while the sum is 32.
Adding to 141131144321312 its reverse (213123441131141), we get a palindrome (354254585452453).
The spelling of 141131144321312 in words is "one hundred forty-one trillion, one hundred thirty-one billion, one hundred forty-four million, three hundred twenty-one thousand, three hundred twelve".
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