14113121100223 has 2 divisors, whose sum is σ = 14113121100224. Its totient is φ = 14113121100222.

The previous prime is 14113121100203. The next prime is 14113121100233. The reversal of 14113121100223 is 32200112131141.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14113121100223 - 2⁵ = 14113121100191 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14113121100194 and 14113121100203.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14113121100203) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7056560550111 + 7056560550112.

It is an arithmetic number, because the mean of its divisors is an integer number (7056560550112).

Almost surely, 2^{14113121100223} is an apocalyptic number.

14113121100223 is a deficient number, since it is larger than the sum of its proper divisors (1).

14113121100223 is an equidigital number, since it uses as much as digits as its factorization.

14113121100223 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 288, while the sum is 22.

Adding to 14113121100223 its reverse (32200112131141), we get a palindrome (46313233231364).

The spelling of 14113121100223 in words is "fourteen trillion, one hundred thirteen billion, one hundred twenty-one million, one hundred thousand, two hundred twenty-three".