141131232220001 has 2 divisors, whose sum is σ = 141131232220002. Its totient is φ = 141131232220000.

The previous prime is 141131232219811. The next prime is 141131232220003. The reversal of 141131232220001 is 100022232131141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 117102373318225 + 24028858901776 = 10821385^2 + 4901924^2 .

It is a cyclic number.

It is not a de Polignac number, because 141131232220001 - 2²⁶ = 141131165111137 is a prime.

Together with 141131232220003, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (141131232220003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70565616110000 + 70565616110001.

It is an arithmetic number, because the mean of its divisors is an integer number (70565616110001).

Almost surely, 2^{141131232220001} is an apocalyptic number.

It is an amenable number.

141131232220001 is a deficient number, since it is larger than the sum of its proper divisors (1).

141131232220001 is an equidigital number, since it uses as much as digits as its factorization.

141131232220001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 141131232220001 its reverse (100022232131141), we get a palindrome (241153464351142).

The spelling of 141131232220001 in words is "one hundred forty-one trillion, one hundred thirty-one billion, two hundred thirty-two million, two hundred twenty thousand, one".