Base | Representation |
---|---|
bin | 1100110101011111111000… |
… | …1011101110100000000000 |
3 | 1211222012201102000022002101 |
4 | 3031113332023232200000 |
5 | 3322212344401214042 |
6 | 50003310155000144 |
7 | 2654435022053551 |
oct | 315277613564000 |
9 | 54865642008071 |
10 | 14113232054272 |
11 | 455142a621a2a |
12 | 16bb2a4a39054 |
13 | 7b4b44c336b0 |
14 | 36b1269c2328 |
15 | 1971b6b266b7 |
hex | cd5fe2ee800 |
14113232054272 has 48 divisors (see below), whose sum is σ = 30390309314820. Its totient is φ = 6513799397376.
The previous prime is 14113232054239. The next prime is 14113232054329. The reversal of 14113232054272 is 27245023231141.
14113232054272 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in 2 ways, for example, as 14062380000256 + 50852054016 = 3749984^2 + 225504^2 .
It is a super-3 number, since 3×141132320542723 (a number of 40 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 265020553 + ... + 265073800.
Almost surely, 214113232054272 is an apocalyptic number.
It is an amenable number.
14113232054272 is an abundant number, since it is smaller than the sum of its proper divisors (16277077260548).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14113232054272 is an equidigital number, since it uses as much as digits as its factorization.
14113232054272 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 530094388 (or 530094368 counting only the distinct ones).
The product of its (nonzero) digits is 80640, while the sum is 37.
The spelling of 14113232054272 in words is "fourteen trillion, one hundred thirteen billion, two hundred thirty-two million, fifty-four thousand, two hundred seventy-two".
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