Base | Representation |
---|---|
bin | 11010010010011011… |
… | …11110111100001010 |
3 | 1100102120200010220012 |
4 | 31021031332330022 |
5 | 212401001214310 |
6 | 10252241031522 |
7 | 1006512051566 |
oct | 151115767412 |
9 | 40376603805 |
10 | 14113304330 |
11 | 5a92657484 |
12 | 289a6255a2 |
13 | 143bc30268 |
14 | 97c56c6a6 |
15 | 579064c05 |
hex | 34937ef0a |
14113304330 has 32 divisors (see below), whose sum is σ = 25508001600. Its totient is φ = 5622244992.
The previous prime is 14113304327. The next prime is 14113304339. The reversal of 14113304330 is 3340331141.
It is a super-2 number, since 2×141133043302 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 14113304296 and 14113304305.
It is not an unprimeable number, because it can be changed into a prime (14113304339) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3063809 + ... + 3068411.
It is an arithmetic number, because the mean of its divisors is an integer number (797125050).
Almost surely, 214113304330 is an apocalyptic number.
14113304330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
14113304330 is a deficient number, since it is larger than the sum of its proper divisors (11394697270).
14113304330 is a wasteful number, since it uses less digits than its factorization.
14113304330 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5798.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 14113304330 its reverse (3340331141), we get a palindrome (17453635471).
The spelling of 14113304330 in words is "fourteen billion, one hundred thirteen million, three hundred four thousand, three hundred thirty".
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