14113330211131 has 2 divisors, whose sum is σ = 14113330211132. Its totient is φ = 14113330211130.

The previous prime is 14113330211117. The next prime is 14113330211171. The reversal of 14113330211131 is 13111203331141.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 14113330211131 - 2⁹ = 14113330210619 is a prime.

It is a super-2 number, since 2×14113330211131² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14113330211096 and 14113330211105.

It is not a weakly prime, because it can be changed into another prime (14113330211171) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7056665105565 + 7056665105566.

It is an arithmetic number, because the mean of its divisors is an integer number (7056665105566).

Almost surely, 2^{14113330211131} is an apocalyptic number.

14113330211131 is a deficient number, since it is larger than the sum of its proper divisors (1).

14113330211131 is an equidigital number, since it uses as much as digits as its factorization.

14113330211131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648, while the sum is 25.

Adding to 14113330211131 its reverse (13111203331141), we get a palindrome (27224533542272).

The spelling of 14113330211131 in words is "fourteen trillion, one hundred thirteen billion, three hundred thirty million, two hundred eleven thousand, one hundred thirty-one".