Base | Representation |
---|---|
bin | 100000000101110000101110… |
… | …001111011000100000000011 |
3 | 200111201012222101102120100021 |
4 | 200011300232033120200003 |
5 | 121444312201142143021 |
6 | 1220055442302434311 |
7 | 41504360150660242 |
oct | 4005605617304003 |
9 | 614635871376307 |
10 | 141133401131011 |
11 | 40a73380664343 |
12 | 139b4722592997 |
13 | 6099a903b1603 |
14 | 26bcc707c2959 |
15 | 114b30c493c41 |
hex | 805c2e3d8803 |
141133401131011 has 2 divisors, whose sum is σ = 141133401131012. Its totient is φ = 141133401131010.
The previous prime is 141133401130979. The next prime is 141133401131131. The reversal of 141133401131011 is 110131104331141.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 141133401131011 - 25 = 141133401130979 is a prime.
It is not a weakly prime, because it can be changed into another prime (141133401141011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70566700565505 + 70566700565506.
It is an arithmetic number, because the mean of its divisors is an integer number (70566700565506).
Almost surely, 2141133401131011 is an apocalyptic number.
141133401131011 is a deficient number, since it is larger than the sum of its proper divisors (1).
141133401131011 is an equidigital number, since it uses as much as digits as its factorization.
141133401131011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 25.
Adding to 141133401131011 its reverse (110131104331141), we get a palindrome (251264505462152).
The spelling of 141133401131011 in words is "one hundred forty-one trillion, one hundred thirty-three billion, four hundred one million, one hundred thirty-one thousand, eleven".
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