Base | Representation |
---|---|
bin | 11010010010011100… |
… | …10111010101010001 |
3 | 1100102120212012221121 |
4 | 31021032113111101 |
5 | 212401012413431 |
6 | 10252243122241 |
7 | 1006512646066 |
oct | 151116272521 |
9 | 40376765847 |
10 | 14113404241 |
11 | 5a92715552 |
12 | 289a673381 |
13 | 143bc66891 |
14 | 97c596c6d |
15 | 579084611 |
hex | 349397551 |
14113404241 has 2 divisors, whose sum is σ = 14113404242. Its totient is φ = 14113404240.
The previous prime is 14113404223. The next prime is 14113404247. The reversal of 14113404241 is 14240431141.
14113404241 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10924430400 + 3188973841 = 104520^2 + 56471^2 .
It is a cyclic number.
It is not a de Polignac number, because 14113404241 - 27 = 14113404113 is a prime.
It is not a weakly prime, because it can be changed into another prime (14113404247) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7056702120 + 7056702121.
It is an arithmetic number, because the mean of its divisors is an integer number (7056702121).
Almost surely, 214113404241 is an apocalyptic number.
It is an amenable number.
14113404241 is a deficient number, since it is larger than the sum of its proper divisors (1).
14113404241 is an equidigital number, since it uses as much as digits as its factorization.
14113404241 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 14113404241 its reverse (14240431141), we get a palindrome (28353835382).
The spelling of 14113404241 in words is "fourteen billion, one hundred thirteen million, four hundred four thousand, two hundred forty-one".
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