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1411341000414 = 23235223500069
BaseRepresentation
bin10100100010011010011…
…110101001111011011110
311222220220210002022100020
4110202122132221323132
5141110411244003124
63000205555413010
7203652226365132
oct24423236517336
94886823068306
101411341000414
114a4601223804
121a963b2b4166
13a31203862c7
144c4488c33c2
1526aa3b0b379
hex1489a7a9ede

1411341000414 has 8 divisors (see below), whose sum is σ = 2822682000840. Its totient is φ = 470447000136.

The previous prime is 1411341000383. The next prime is 1411341000463. The reversal of 1411341000414 is 4140001431141.

It is a sphenic number, since it is the product of 3 distinct primes.

1411341000414 is an admirable number.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 117611750029 + ... + 117611750040.

It is an arithmetic number, because the mean of its divisors is an integer number (352835250105).

Almost surely, 21411341000414 is an apocalyptic number.

1411341000414 is a primitive abundant number, since it is smaller than the sum of its proper divisors, none of which is abundant.

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1411341000414 is a wasteful number, since it uses less digits than its factorization.

1411341000414 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 235223500074.

The product of its (nonzero) digits is 768, while the sum is 24.

Adding to 1411341000414 its reverse (4140001431141), we get a palindrome (5551342431555).

The spelling of 1411341000414 in words is "one trillion, four hundred eleven billion, three hundred forty-one million, four hundred fourteen", and thus it is an aban number.

Divisors: 1 2 3 6 235223500069 470447000138 705670500207 1411341000414