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141134330213 is a prime number
BaseRepresentation
bin1000001101110001000…
…0101111100101100101
3111111021220010211021022
42003130100233211211
54303020342031323
6144500342300525
713124304004322
oct2033420574545
9444256124238
10141134330213
1154944717228
1223429727745
13104028a28c6
146b8c145b49
153a105d94c8
hex20dc42f965

141134330213 has 2 divisors, whose sum is σ = 141134330214. Its totient is φ = 141134330212.

The previous prime is 141134330203. The next prime is 141134330219. The reversal of 141134330213 is 312033431141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 131596268644 + 9538061569 = 362762^2 + 97663^2 .

It is a cyclic number.

It is not a de Polignac number, because 141134330213 - 214 = 141134313829 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (141134330219) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70567165106 + 70567165107.

It is an arithmetic number, because the mean of its divisors is an integer number (70567165107).

Almost surely, 2141134330213 is an apocalyptic number.

It is an amenable number.

141134330213 is a deficient number, since it is larger than the sum of its proper divisors (1).

141134330213 is an equidigital number, since it uses as much as digits as its factorization.

141134330213 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2592, while the sum is 26.

Adding to 141134330213 its reverse (312033431141), we get a palindrome (453167761354).

The spelling of 141134330213 in words is "one hundred forty-one billion, one hundred thirty-four million, three hundred thirty thousand, two hundred thirteen".