14113434330 has 80 divisors (see below), whose sum is σ = 37971295560. Its totient is φ = 3761417088.

The previous prime is 14113434319. The next prime is 14113434371. The reversal of 14113434330 is 3343431141.

It can be written as a sum of positive squares in 4 ways, for example, as 13182024969 + 931409361 = 114813^2 + 30519^2 .

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 14113434294 and 14113434303.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 1808076 + ... + 1815864.

Almost surely, 2^14113434330 is an apocalyptic number.

14113434330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

14113434330 is an abundant number, since it is smaller than the sum of its proper divisors (23857861230).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

14113434330 is a wasteful number, since it uses less digits than its factorization.

14113434330 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10045 (or 10036 counting only the distinct ones).

The product of its (nonzero) digits is 5184, while the sum is 27.

Adding to 14113434330 its reverse (3343431141), we get a palindrome (17456865471).

The spelling of 14113434330 in words is "fourteen billion, one hundred thirteen million, four hundred thirty-four thousand, three hundred thirty".