14113521354481 has 2 divisors, whose sum is σ = 14113521354482. Its totient is φ = 14113521354480.

The previous prime is 14113521354479. The next prime is 14113521354529. The reversal of 14113521354481 is 18445312531141.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12780053006400 + 1333468348081 = 3574920^2 + 1154759^2 .

It is a cyclic number.

It is not a de Polignac number, because 14113521354481 - 2¹ = 14113521354479 is a prime.

It is a super-2 number, since 2×14113521354481² (a number of 27 digits) contains 22 as substring.

Together with 14113521354479, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (14113561354481) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7056760677240 + 7056760677241.

It is an arithmetic number, because the mean of its divisors is an integer number (7056760677241).

Almost surely, 2^{14113521354481} is an apocalyptic number.

It is an amenable number.

14113521354481 is a deficient number, since it is larger than the sum of its proper divisors (1).

14113521354481 is an equidigital number, since it uses as much as digits as its factorization.

14113521354481 is an evil number, because the sum of its binary digits is even.

The product of its digits is 230400, while the sum is 43.

The spelling of 14113521354481 in words is "fourteen trillion, one hundred thirteen billion, five hundred twenty-one million, three hundred fifty-four thousand, four hundred eighty-one".