14114013424283 has 2 divisors, whose sum is σ = 14114013424284. Its totient is φ = 14114013424282.

The previous prime is 14114013424223. The next prime is 14114013424307. The reversal of 14114013424283 is 38242431041141.

14114013424283 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14114013424283 - 2¹⁴ = 14114013407899 is a prime.

It is not a weakly prime, because it can be changed into another prime (14114013424223) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7057006712141 + 7057006712142.

It is an arithmetic number, because the mean of its divisors is an integer number (7057006712142).

Almost surely, 2^{14114013424283} is an apocalyptic number.

14114013424283 is a deficient number, since it is larger than the sum of its proper divisors (1).

14114013424283 is an equidigital number, since it uses as much as digits as its factorization.

14114013424283 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 73728, while the sum is 38.

The spelling of 14114013424283 in words is "fourteen trillion, one hundred fourteen billion, thirteen million, four hundred twenty-four thousand, two hundred eighty-three".