14114013424531 has 2 divisors, whose sum is σ = 14114013424532. Its totient is φ = 14114013424530.

The previous prime is 14114013424519. The next prime is 14114013424613. The reversal of 14114013424531 is 13542431041141.

14114013424531 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 14114013424531 - 2¹³ = 14114013416339 is a prime.

It is a super-3 number, since 3×14114013424531³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (14114013427531) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7057006712265 + 7057006712266.

It is an arithmetic number, because the mean of its divisors is an integer number (7057006712266).

Almost surely, 2^{14114013424531} is an apocalyptic number.

14114013424531 is a deficient number, since it is larger than the sum of its proper divisors (1).

14114013424531 is an equidigital number, since it uses as much as digits as its factorization.

14114013424531 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 23040, while the sum is 34.

Adding to 14114013424531 its reverse (13542431041141), we get a palindrome (27656444465672).

The spelling of 14114013424531 in words is "fourteen trillion, one hundred fourteen billion, thirteen million, four hundred twenty-four thousand, five hundred thirty-one".