Base | Representation |
---|---|
bin | 1100110101100011000111… |
… | …1100001110100001101011 |
3 | 1211222021221220222011020112 |
4 | 3031120301330032201223 |
5 | 3322221134201001004 |
6 | 50003532254444535 |
7 | 2654465364661421 |
oct | 315306174164153 |
9 | 54867856864215 |
10 | 14114100406379 |
11 | 45518357a87a6 |
12 | 16bb4a780374b |
13 | 7b4c52ac8ccc |
14 | 36b1aa061111 |
15 | 197217ea0e6e |
hex | cd631f0e86b |
14114100406379 has 2 divisors, whose sum is σ = 14114100406380. Its totient is φ = 14114100406378.
The previous prime is 14114100406339. The next prime is 14114100406381. The reversal of 14114100406379 is 97360400141141.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14114100406379 is a prime.
Together with 14114100406381, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (14114100406339) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7057050203189 + 7057050203190.
It is an arithmetic number, because the mean of its divisors is an integer number (7057050203190).
Almost surely, 214114100406379 is an apocalyptic number.
14114100406379 is a deficient number, since it is larger than the sum of its proper divisors (1).
14114100406379 is an equidigital number, since it uses as much as digits as its factorization.
14114100406379 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72576, while the sum is 41.
The spelling of 14114100406379 in words is "fourteen trillion, one hundred fourteen billion, one hundred million, four hundred six thousand, three hundred seventy-nine".
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