Base | Representation |
---|---|
bin | 1100110101100011001000… |
… | …0100001110100001010111 |
3 | 1211222021222001220200222002 |
4 | 3031120302010032201113 |
5 | 3322221140220103021 |
6 | 50003532411425515 |
7 | 2654465421544463 |
oct | 315306204164127 |
9 | 54867861820862 |
10 | 14114102503511 |
11 | 4551836a0036a |
12 | 16bb4a845529b |
13 | 7b4c5338170a |
14 | 36b1aa4494a3 |
15 | 19721826750b |
hex | cd63210e857 |
14114102503511 has 2 divisors, whose sum is σ = 14114102503512. Its totient is φ = 14114102503510.
The previous prime is 14114102503469. The next prime is 14114102503517. The reversal of 14114102503511 is 11530520141141.
It is a strong prime.
It is an emirp because it is prime and its reverse (11530520141141) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14114102503511 - 226 = 14114035394647 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14114102503517) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7057051251755 + 7057051251756.
It is an arithmetic number, because the mean of its divisors is an integer number (7057051251756).
Almost surely, 214114102503511 is an apocalyptic number.
14114102503511 is a deficient number, since it is larger than the sum of its proper divisors (1).
14114102503511 is an equidigital number, since it uses as much as digits as its factorization.
14114102503511 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2400, while the sum is 29.
Adding to 14114102503511 its reverse (11530520141141), we get a palindrome (25644622644652).
The spelling of 14114102503511 in words is "fourteen trillion, one hundred fourteen billion, one hundred two million, five hundred three thousand, five hundred eleven".
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