Base | Representation |
---|---|
bin | 1100110101100011001000… |
… | …0110010000010101011111 |
3 | 1211222021222002220201100102 |
4 | 3031120302012100111133 |
5 | 3322221140334111411 |
6 | 50003532431051315 |
7 | 2654465426220623 |
oct | 315306206202537 |
9 | 54867862821312 |
10 | 14114103035231 |
11 | 4551837233901 |
12 | 16bb4a8670b3b |
13 | 7b4c53509744 |
14 | 36b1aa547183 |
15 | 19721831ed3b |
hex | cd63219055f |
14114103035231 has 2 divisors, whose sum is σ = 14114103035232. Its totient is φ = 14114103035230.
The previous prime is 14114103035191. The next prime is 14114103035243. The reversal of 14114103035231 is 13253030141141.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14114103035231 is a prime.
It is a super-2 number, since 2×141141030352312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 14114103035194 and 14114103035203.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14114103035831) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7057051517615 + 7057051517616.
It is an arithmetic number, because the mean of its divisors is an integer number (7057051517616).
Almost surely, 214114103035231 is an apocalyptic number.
14114103035231 is a deficient number, since it is larger than the sum of its proper divisors (1).
14114103035231 is an equidigital number, since it uses as much as digits as its factorization.
14114103035231 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4320, while the sum is 29.
Adding to 14114103035231 its reverse (13253030141141), we get a palindrome (27367133176372).
The spelling of 14114103035231 in words is "fourteen trillion, one hundred fourteen billion, one hundred three million, thirty-five thousand, two hundred thirty-one".
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