141141134000413 has 2 divisors, whose sum is σ = 141141134000414. Its totient is φ = 141141134000412.

The previous prime is 141141134000389. The next prime is 141141134000527. The reversal of 141141134000413 is 314000431141141.

141141134000413 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 109382251208409 + 31758882792004 = 10458597^2 + 5635502^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-141141134000413 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (141141134000813) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70570567000206 + 70570567000207.

It is an arithmetic number, because the mean of its divisors is an integer number (70570567000207).

Almost surely, 2^{141141134000413} is an apocalyptic number.

It is an amenable number.

141141134000413 is a deficient number, since it is larger than the sum of its proper divisors (1).

141141134000413 is an equidigital number, since it uses as much as digits as its factorization.

141141134000413 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2304, while the sum is 28.

Adding to 141141134000413 its reverse (314000431141141), we get a palindrome (455141565141554).

The spelling of 141141134000413 in words is "one hundred forty-one trillion, one hundred forty-one billion, one hundred thirty-four million, four hundred thirteen", and thus it is an aban number.