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141143025437 is a prime number
BaseRepresentation
bin1000001101110011000…
…1111010011100011101
3111111022111111120212122
42003130301322130131
54303030103303222
6144501252512325
713124440630661
oct2033461723435
9444274446778
10141143025437
1154949616067
122343061b6a5
13104046285cb
146b8d36a8a1
153a11255a42
hex20dcc7a71d

141143025437 has 2 divisors, whose sum is σ = 141143025438. Its totient is φ = 141143025436.

The previous prime is 141143025409. The next prime is 141143025461. The reversal of 141143025437 is 734520341141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 77547768676 + 63595256761 = 278474^2 + 252181^2 .

It is a cyclic number.

It is not a de Polignac number, because 141143025437 - 210 = 141143024413 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 141143025397 and 141143025406.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (141143025407) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70571512718 + 70571512719.

It is an arithmetic number, because the mean of its divisors is an integer number (70571512719).

Almost surely, 2141143025437 is an apocalyptic number.

It is an amenable number.

141143025437 is a deficient number, since it is larger than the sum of its proper divisors (1).

141143025437 is an equidigital number, since it uses as much as digits as its factorization.

141143025437 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 40320, while the sum is 35.

Adding to 141143025437 its reverse (734520341141), we get a palindrome (875663366578).

The spelling of 141143025437 in words is "one hundred forty-one billion, one hundred forty-three million, twenty-five thousand, four hundred thirty-seven".