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14114332325330 = 251974285959607
BaseRepresentation
bin1100110101100011111111…
…0000111011010111010010
31211222022120002100212020022
43031120333300323113102
53322222123033402310
650004011301343442
72654504212156106
oct315307760732722
954868502325208
1014114332325330
114551944701956
1216bb551407b82
137b4c8bb7a863
1436b1ccb91906
1519722d512a55
hexcd63fc3b5d2

14114332325330 has 16 divisors (see below), whose sum is σ = 26742945458880. Its totient is φ = 5348589091632.

The previous prime is 14114332325323. The next prime is 14114332325363. The reversal of 14114332325330 is 3352323341141.

It is a super-3 number, since 3×141143323253303 (a number of 40 digits) contains 333 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 37142979614 + ... + 37142979993.

It is an arithmetic number, because the mean of its divisors is an integer number (1671434091180).

Almost surely, 214114332325330 is an apocalyptic number.

14114332325330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

14114332325330 is a deficient number, since it is larger than the sum of its proper divisors (12628613133550).

14114332325330 is a wasteful number, since it uses less digits than its factorization.

14114332325330 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 74285959633.

The product of its (nonzero) digits is 77760, while the sum is 35.

Adding to 14114332325330 its reverse (3352323341141), we get a palindrome (17466655666471).

The spelling of 14114332325330 in words is "fourteen trillion, one hundred fourteen billion, three hundred thirty-two million, three hundred twenty-five thousand, three hundred thirty".

Divisors: 1 2 5 10 19 38 95 190 74285959607 148571919214 371429798035 742859596070 1411433232533 2822866465066 7057166162665 14114332325330