Base | Representation |
---|---|
bin | 1100110101100100110011… |
… | …0011001010001011110011 |
3 | 1211222100010022212101212112 |
4 | 3031121030303022023303 |
5 | 3322223100024423011 |
6 | 50004045112515535 |
7 | 2654512506041561 |
oct | 315311463121363 |
9 | 54870108771775 |
10 | 14114551014131 |
11 | 4551a47099aa7 |
12 | 16bb5b26abbab |
13 | 7b4cc5279509 |
14 | 36b20dc3aa31 |
15 | 19724280e58b |
hex | cd64ccca2f3 |
14114551014131 has 2 divisors, whose sum is σ = 14114551014132. Its totient is φ = 14114551014130.
The previous prime is 14114551014073. The next prime is 14114551014191. The reversal of 14114551014131 is 13141015541141.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14114551014131 is a prime.
It is a super-2 number, since 2×141145510141312 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (14114551014191) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7057275507065 + 7057275507066.
It is an arithmetic number, because the mean of its divisors is an integer number (7057275507066).
Almost surely, 214114551014131 is an apocalyptic number.
14114551014131 is a deficient number, since it is larger than the sum of its proper divisors (1).
14114551014131 is an equidigital number, since it uses as much as digits as its factorization.
14114551014131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4800, while the sum is 32.
Adding to 14114551014131 its reverse (13141015541141), we get a palindrome (27255566555272).
The spelling of 14114551014131 in words is "fourteen trillion, one hundred fourteen billion, five hundred fifty-one million, fourteen thousand, one hundred thirty-one".
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