Base | Representation |
---|---|
bin | 10000110100111… |
… | …00011101011001 |
3 | 100211121011110022 |
4 | 20122130131121 |
5 | 242113300131 |
6 | 22001200225 |
7 | 3332520104 |
oct | 1032343531 |
9 | 324534408 |
10 | 141150041 |
11 | 7274812a |
12 | 3b330075 |
13 | 23320946 |
14 | 14a6373b |
15 | c5d237b |
hex | 869c759 |
141150041 has 2 divisors, whose sum is σ = 141150042. Its totient is φ = 141150040.
The previous prime is 141150029. The next prime is 141150043. The reversal of 141150041 is 140051141.
141150041 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 120538441 + 20611600 = 10979^2 + 4540^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-141150041 is a prime.
It is a super-3 number, since 3×1411500413 (a number of 25 digits) contains 333 as substring.
Together with 141150043, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (141150043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70575020 + 70575021.
It is an arithmetic number, because the mean of its divisors is an integer number (70575021).
Almost surely, 2141150041 is an apocalyptic number.
It is an amenable number.
141150041 is a deficient number, since it is larger than the sum of its proper divisors (1).
141150041 is an equidigital number, since it uses as much as digits as its factorization.
141150041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 80, while the sum is 17.
The square root of 141150041 is about 11880.6582730083. The cubic root of 141150041 is about 520.6673397052.
The spelling of 141150041 in words is "one hundred forty-one million, one hundred fifty thousand, forty-one".
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