Base | Representation |
---|---|
bin | 11010010010101011… |
… | …01110110000111111 |
3 | 1100102201111022202202 |
4 | 31021111232300333 |
5 | 212402011211411 |
6 | 10252352342115 |
7 | 1006535240564 |
oct | 151125566077 |
9 | 40381438682 |
10 | 14115335231 |
11 | 5a93814308 |
12 | 289b24493b |
13 | 143c49178a |
14 | 97c93a86b |
15 | 57931683b |
hex | 34956ec3f |
14115335231 has 2 divisors, whose sum is σ = 14115335232. Its totient is φ = 14115335230.
The previous prime is 14115335219. The next prime is 14115335249. The reversal of 14115335231 is 13253351141.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14115335231 is a prime.
It is a super-2 number, since 2×141153352312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 14115335194 and 14115335203.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14115635231) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7057667615 + 7057667616.
It is an arithmetic number, because the mean of its divisors is an integer number (7057667616).
Almost surely, 214115335231 is an apocalyptic number.
14115335231 is a deficient number, since it is larger than the sum of its proper divisors (1).
14115335231 is an equidigital number, since it uses as much as digits as its factorization.
14115335231 is an evil number, because the sum of its binary digits is even.
The product of its digits is 5400, while the sum is 29.
Adding to 14115335231 its reverse (13253351141), we get a palindrome (27368686372).
The spelling of 14115335231 in words is "fourteen billion, one hundred fifteen million, three hundred thirty-five thousand, two hundred thirty-one".
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